Ejercicio
$\left(\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}\right)^6$
Solución explicada paso por paso
Respuesta final al problema
$\left(\begin{matrix}6\\0\end{matrix}\right)\cdot \left(2+\sqrt{3}\right)^{3}+\left(\begin{matrix}6\\1\end{matrix}\right)\sqrt{\left(2+\sqrt{3}\right)^{5}}\sqrt{2-\sqrt{3}}+\left(2-\sqrt{3}\right)\left(\begin{matrix}6\\2\end{matrix}\right)\cdot \left(2+\sqrt{3}\right)^{2}+\left(\begin{matrix}6\\3\end{matrix}\right)\sqrt{\left(2+\sqrt{3}\right)^{3}}\sqrt{\left(2-\sqrt{3}\right)^{3}}+\left(2+\sqrt{3}\right)\left(\begin{matrix}6\\4\end{matrix}\right)\cdot \left(2-\sqrt{3}\right)^{2}+\left(\begin{matrix}6\\5\end{matrix}\right)\sqrt{2+\sqrt{3}}\sqrt{\left(2-\sqrt{3}\right)^{5}}+\left(\begin{matrix}6\\6\end{matrix}\right)\cdot \left(2-\sqrt{3}\right)^{3}$