Resolver la ecuación logarítmica $\log \left(4000x\right)-\log \left(x^2\right)=3$

$\log_3\left(x+4\right)+\log_3\left(x-4\right)=2$

$\log_x\left(64\right)=3$

$log\left(x+1\right)=log\left(x-1\right)+3$

$\log\left(x-1\right)+\log\left(x+1\right)=2\log\left(x+2\right)$

$\log_x\left(\frac{1}{8}\right)=-3$

$\log_x\left(100\right)-\log_x\left(25\right)=2$

$\log_2\left(x\right)-\log_2\left(10\right)=\log_2\left(9.3\right)$